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Simplifying b4 + 3b2 + -4 = 0 Reorder the terms: -4 + 3b2 + b4 = 0 Solving -4 + 3b2 + b4 = 0 Solving for variable 'b'. Factor a trinomial. (-4 + -1b2)(1 + -1b2) = 0 Factor a difference between two squares. (-4 + -1b2)((1 + b)(1 + -1b)) = 0Subproblem 1
Set the factor '(-4 + -1b2)' equal to zero and attempt to solve: Simplifying -4 + -1b2 = 0 Solving -4 + -1b2 = 0 Move all terms containing b to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1b2 = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1b2 = 0 + 4 -1b2 = 0 + 4 Combine like terms: 0 + 4 = 4 -1b2 = 4 Divide each side by '-1'. b2 = -4 Simplifying b2 = -4 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.Subproblem 2
Set the factor '(1 + b)' equal to zero and attempt to solve: Simplifying 1 + b = 0 Solving 1 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + b = 0 + -1 Combine like terms: 1 + -1 = 0 0 + b = 0 + -1 b = 0 + -1 Combine like terms: 0 + -1 = -1 b = -1 Simplifying b = -1Subproblem 3
Set the factor '(1 + -1b)' equal to zero and attempt to solve: Simplifying 1 + -1b = 0 Solving 1 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1b = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1b = 0 + -1 -1b = 0 + -1 Combine like terms: 0 + -1 = -1 -1b = -1 Divide each side by '-1'. b = 1 Simplifying b = 1Solution
b = {-1, 1}
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